Another numismatist decides to divide his coin collection among his children. The oldest gets 1/2 of the collection, the second gets 1/3, the third gets 1/n, where n is a natural number, and the youngest gets the remaining 50 coins. How many coins at most can there be in the collection?
Answer
There are 2,100 coins in the collection and n=7.
1050 + 700 + 300 + 50 = 2,100
